algebra
posted by Hossein .
There are 51 students in a certain class. The number of females is 5 less than 3 times the number of males. find the number of females and the number of males in the class.

Find three consecutive integers such that the sum of the smallest and largest integer is equal to twice the middle number

number of males  x
number of females  3x5
Can you form the equation from here and solve it? 
Please do not post a new question as a reply to somebody else's problem.
Tutors might think it has been answered and not look at it.
I will set it up for you...
1st integer  x
2nd integer x+1
3rd integer x + 2
"smallest plus largest equals twice the middle"
x + (x+2) = 2(x+1)
solve....
ahhh, glancing at this equation it is obvious that you will get
0=0
that means that it will be true for all consecutive even integers.
e.g. let's try 4,5,6
is 4+6 = 2(5) ? YES