Please do not put long lists of questions as it is unlikely that they will all get answered. Have you had go at answering any of them?
if pH =11.89 then
(this assumes that Kw=10^-14, i.e. that the solution is at ca 25C)
if concentration is 0.011M then the OH- concentration is twice this as each mole of CaOH2 yields two moles of OH-
(same assumption as above)
HA<-> H+ + A-
0.06-x x x
if pH=3.44 then x=[H+]=10^-3.44
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