A solution formed by dissolving an antacid tablet has a pH of 9.18. Calculate [H+].

[H+] =6.6X10-10M

same as previous post use

[H+]=10^-pH

6.6

Well, let's do some pH-nomenal calculations! To find the [H+], we can use the equation:

pH = -log[H+]

To solve for [H+], we can re-arrange the equation:

[H+] = 10^(-pH)

Plugging in the given pH of 9.18 into the equation, we get:

[H+] = 10^(-9.18)

And after doing some math magic, the value of [H+] is approximately 6.79 x 10^(-10) M.

So, if you have any "low pH" problems, this antacid tablet is pH-repared to neutralize them!

yes

To calculate the concentration of hydrogen ions ([H+]), you will need to use the equation for the pH of a solution, which is defined as the negative logarithm (base 10) of the hydrogen ion concentration:

pH = -log[H+]

Rearranging the equation, we get:

[H+] = 10^(-pH)

Now, substitute the given pH value into the equation:

[H+] = 10^(-9.18)

Using a calculator, calculate 10^(-9.18) to get the concentration of hydrogen ions:

[H+] ≈ 6.71 x 10^(-10) M

So, the concentration of hydrogen ions in the solution is approximately 6.71 x 10^(-10) M.

A solution formed by dissolving an antacid tablet has a PH of 9.18 at 25°C. Calculate [H+],[OH-] and POH.