Posted by **Ricky** on Thursday, January 20, 2011 at 12:20am.

A Ferris Wheel, 24.0 m in diameter, rotates once every 12.5s. What is the fractional change in a person's apparent weight: a) at the top, and b) at the bottom?

I need to know if I'm doing this right. Here's my work:

Equation Used:

Net Force = [(4(pi)^2)(R)(M)] / [T^2]

M=mass

T=Period

R=Radius

FN= Normal Force

mg = weight

Top:

mg - FN = [(4(pi)^2)(R)(M)] / [T^2]

FN = (6.77M) Newtons

Bottom:

FN - mg = [(4(pi)^2)(R)(M)] / [T^2]

FN = (12.8M) Newtons

This is what I got so far, but I'm not sure what it means by the fractional change in a person's apparent weight. So where do I go from here?

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