Posted by **Ricky** on Thursday, January 20, 2011 at 12:20am.

A Ferris Wheel, 24.0 m in diameter, rotates once every 12.5s. What is the fractional change in a person's apparent weight: a) at the top, and b) at the bottom?

I need to know if I'm doing this right. Here's my work:

Equation Used:

Net Force = [(4(pi)^2)(R)(M)] / [T^2]

M=mass

T=Period

R=Radius

FN= Normal Force

mg = weight

Top:

mg - FN = [(4(pi)^2)(R)(M)] / [T^2]

FN = (6.77M) Newtons

Bottom:

FN - mg = [(4(pi)^2)(R)(M)] / [T^2]

FN = (12.8M) Newtons

This is what I got so far, but I'm not sure what it means by the fractional change in a person's apparent weight. So where do I go from here?

## Answer This Question

## Related Questions

- Physics - A Ferris wheel, 24.0 m in diameter, rotates once every 12.5 s(see the ...
- Physics - A Ferris wheel is 60 meters in diameter and rotates once every 12.5s...
- math - A Ferris wheel 28.0m in diameter rotates once every 21.0s. What is the ...
- Physics - A Ferris wheel 26.0m in diameter rotates once every 19.0s What is the ...
- physic - A Ferris wheel 26.0m in diameter rotates once every 15.0s . What is the...
- physic - A Ferris wheel 26.0m in diameter rotates once every 15.0s What is the ...
- physic - A Ferris wheel 26.0m in diameter rotates once every 15.0s What is the ...
- Physics - An 80-ft-diameter Ferris wheel rotates once every 23s. What is the ...
- Physics - In a ferris wheel, one person is at the top and another at the bttom. ...
- Physics - I have some trouble starting the problem. I don't know what equations ...

More Related Questions