WHAT IS MAGNITUDE OF NORMAL FORCE IN FIGURE WITH V=+3M/S

+10n INSIDE BOX IS 5KG

To find the magnitude of the normal force in the given scenario, we first need to understand the concept of normal force. Normal force is the force exerted by a surface to support the weight of an object resting on it. It acts perpendicular to the surface.

In this case, you have provided information about a box with a velocity of +3 m/s and a mass of 5 kg. However, the velocity alone is not sufficient to determine the normal force.

To calculate the magnitude of the normal force, we need to consider the net force acting on the object. According to Newton's second law of motion, the net force on an object is equal to the product of its mass and acceleration.

Since you have only provided information about the velocity, we will assume that the box is at a constant velocity, which means that the acceleration is zero. In this case, the net force acting on the box is also zero.

Therefore, the normal force must be equal in magnitude but opposite in direction to the gravitational force acting on the box.

To calculate the gravitational force, we use the formula: gravitational force = mass * acceleration due to gravity.

The acceleration due to gravity on Earth is approximately 9.8 m/s².

So, the gravitational force acting on the 5 kg box can be calculated as follows:

gravitational force = mass * acceleration due to gravity
= 5 kg * 9.8 m/s²
= 49 N

Since the net force is zero when the box is moving at a constant velocity, the magnitude of the normal force must be equal to 49 N, but acting in the opposite direction to the gravitational force.

Therefore, the magnitude of the normal force in this scenario is 49 N.