Posted by **Anonymous** on Wednesday, January 19, 2011 at 10:18pm.

Lines A and B are perpendicular and have the same x-intercept. The equation of line A

is x + 2y - 4 = 0 . Determine the y-intercept of line B.

A.-8

B.-2

C. 4

D. 8

This is the work that I did:

x + 2y - 4 = 0

+4 +4

x+2y = 4

-x -x

2y = -x+4

divide both sides by 2

and I got -1/2x+2

I thought that the answer would be -2 maybe but its -8. How is it -8?

- ALGEBRA -
**helper**, Wednesday, January 19, 2011 at 11:32pm
x + 2y - 4 = 0

x + 2y = 4

to find x-intercept, y = 0

x + 2(0) = 4

x = 4

x-intercept = (4.0)

slope intercept form (which you got right above) y = mx + b

for Line A is y = -1/2 x + 2

slope m = -1/2

If two lines are perpendicular, the slope of one is the negative reciprocal of the slope of the other.

Slope of Line B = ?

Line B through point (4,0)(line A and B have the same x-intercept)

To write equation of Line B

plug slope m in y = mx + b, and use point (4,0) to solve for b, which is the y-intercept.

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