# MATH_ALGEBRA

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The price to cover ornaments is a fixed amount plus a percentage of the value of the ornaments.
It costs \$32 to insure \$1000 worth of jewellery or \$44.50 to insure \$3500 worth of jewellery.
What is the fixed amount to insure jewellery?

A. \$27.00
B. \$31.25
C. \$44.65
D. \$58.82

This is what I got told to you, but like y do u have to subtract, I get the first equation, I don't get the second, and It still has to be solved. I really don't understand, please help

F = fixed amount
P = percentage

F + P(1000) = 32
-[f + p(3500) = 44.50]

• MATH_ALGEBRA - ,

(1) F + 1000P = 32
(2) F + 3500P = 44.50

you have to solve these 2 equations simultaneously

By elimination method, to eliminate F, multiply one of the equations by -1

-1(F + 1000P = 32)= -F - 1000P = -32

Now ADD these two equations together
-F - 1000P = -32
F + 3500P = 44.50
0 + 2500P = 12.5
2500P = 12.5
P = .005

substitute P = .005 in one of the equations to find F

F + 1000P = 32
F + 1000(.005) = 32
F + 5 = 32
F = 27

What is the fixed amount to insure jewellery?

A. \$27

• MATH_ALGEBRA - ,

Thank you so much Helper

• MATH_ALGEBRA - ,

you're welcome :)