Posted by **Anonymous** on Wednesday, January 19, 2011 at 6:15pm.

What's the slope-intercept equation of line which is parallel to y = 2/5x-3 and passes through point (0,5)

A. y = -5/2x - 3

B. y = -5/2x + 5

C. y = 2/5x + 3

D. y = 2/5x + 5

Its D, but how do u figure that out? please explain step by step.

- MATH-ALGEBRA -
**helper**, Wednesday, January 19, 2011 at 8:08pm
y = 2/5x - 3

P (0,5)

parallel lines have equal slopes

slope intercept form of an equation

y = mx + b

m = slope, b = y-intercept

parallel to y = 2/5x - 3,

and through P(0, 5)

m = 2/5

y intercept = 5

so, the equation would be

D. y = 2/5x + 5

- MATH-ALGEBRA -
**Anonymous**, Wednesday, January 19, 2011 at 8:13pm
Thanks helper, i was confused on how they had gotten 5, but now i understand thanks to ur explanation:)

- MATH-ALGEBRA -
**Idk**, Tuesday, September 25, 2012 at 4:24pm
(Nm^3)^0

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