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MATH-ALGEBRA

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What's the slope-intercept equation of line which is parallel to y = 2/5x-3 and passes through point (0,5)

A. y = -5/2x - 3

B. y = -5/2x + 5

C. y = 2/5x + 3

D. y = 2/5x + 5

Its D, but how do u figure that out? please explain step by step.

  • MATH-ALGEBRA - ,

    y = 2/5x - 3
    P (0,5)

    parallel lines have equal slopes
    slope intercept form of an equation
    y = mx + b
    m = slope, b = y-intercept


    parallel to y = 2/5x - 3,
    and through P(0, 5)
    m = 2/5
    y intercept = 5
    so, the equation would be
    D. y = 2/5x + 5

  • MATH-ALGEBRA - ,

    Thanks helper, i was confused on how they had gotten 5, but now i understand thanks to ur explanation:)

  • MATH-ALGEBRA - ,

    (Nm^3)^0

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