What's the slope-intercept equation of line which is parallel to y = 2/5x-3 and passes through point (0,5)

A. y = -5/2x - 3

B. y = -5/2x + 5

C. y = 2/5x + 3

D. y = 2/5x + 5

Its D, but how do u figure that out? please explain step by step.

y = 2/5x - 3

P (0,5)

parallel lines have equal slopes
slope intercept form of an equation
y = mx + b
m = slope, b = y-intercept

parallel to y = 2/5x - 3,
and through P(0, 5)
m = 2/5
y intercept = 5
so, the equation would be
D. y = 2/5x + 5

Thanks helper, i was confused on how they had gotten 5, but now i understand thanks to ur explanation:)

(Nm^3)^0

Write a​ slope-intercept equation for a line passing through the point ​(​6,3​) that is parallel to y=2/5x+3

To find the slope-intercept equation of a line parallel to another line, we need to understand that parallel lines have the same slope.

First, let's look at the equation of the given line: y = (2/5)x - 3

The slope-intercept form of an equation is y = mx + b, where m represents the slope and b represents the y-intercept.

Since we want the line to be parallel to the given line, it will have the same slope, which is 2/5.

Now, we have the slope (m = 2/5) and a point that the line passes through, which is (0, 5).

We can use the point-slope form of the equation of a line to find the equation of the line parallel to the given line and passing through the point (0, 5).

The point-slope form of an equation is y - y1 = m(x - x1), where (x1, y1) represents the given point (0, 5).

Plugging in the values, we have y - 5 = (2/5)(x - 0).

Simplifying, we get y - 5 = (2/5)x.

Now, let's rearrange the equation to get it in slope-intercept form (y = mx + b):

y = (2/5)x + 5.

So, the equation of the line that is parallel to y = (2/5)x - 3 and passes through the point (0, 5) is y = (2/5)x + 5.

Therefore, the correct answer is option D: y = (2/5)x + 5.