what product is formed from 1-bromo-2 methyl-cyclohexane reaction with CH3ONa and CH3OH...from a substitution reaction
...I got 1-CH3OH-2methly-cyclohexane but it's wrong.
Not sure how to do it
To determine the product formed from the reaction between 1-bromo-2-methyl-cyclohexane and CH3ONa/CH3OH, you need to understand the concept of nucleophilic substitution reactions.
In this case, CH3ONa (sodium methoxide) is the nucleophile that will attack the electrophilic carbon (bearing the bromine) in the 1-bromo-2-methyl-cyclohexane molecule. This will result in the substitution of the bromine atom with the nucleophile.
To understand the product, you need to consider the mechanism of the reaction, which is an SN2 (substitution nucleophilic bimolecular) reaction. In an SN2 reaction, the nucleophile attacks the carbon from the opposite side of the leaving group (bromine in this case), causing a stereospecific inversion of configuration.
To solve this problem, follow these steps:
Step 1: Identify the leaving group. In this case, it is the bromine atom.
Step 2: Draw the structure of the starting compound, 1-bromo-2-methyl-cyclohexane:
CH3
|
CH3-C-Br
|
CH2
Step 3: Determine the nucleophile. In this case, it is CH3ONa (sodium methoxide), which can be represented as CH3O-.
Step 4: Write the reaction mechanism, considering the nucleophile attacking the carbon bearing bromine from the opposite side. This will cause an inversion of the stereochemistry:
CH3
|
CH3-C-Br + CH3O- -> CH3
| |
CH2 CH3
|
CH2
Step 5: Simplify the structure of the product:
CH3
|
CH3-C-OH
|
CH2
The resulting product is 1-methoxy-2-methyl-cyclohexane, where the bromine has been substituted with a methoxy (-OCH3) group.
Note: The name of the product may vary depending on the nomenclature conventions used, but the structure should remain the same.