According to Car and Driver, an Alfa Romeo going 70 mph requires 177 feet to stop. Assuming that the stopping distance is proportional to the square of the velocity, find the stopping distance required by an Alfa Romeo going at 55 mph and at 115 mph.
Y=KR^P
P=2
R=70
Y=177
K=177/4900
USE THESE NOTATION TO THAN INPUT YOUR 55 AND 155 IN FOR R
YOUR ANSERS WILL THAN BE
115=90.31FT
55=109.27
ma chod di ganit ki
To find the stopping distance required by an Alfa Romeo going at 55 mph, we can use the concept that the stopping distance is proportional to the square of the velocity.
Step 1: Set up a proportion using the given information:
- Let "x" represent the stopping distance required by an Alfa Romeo going at 55 mph.
- From the given information, we know that when the speed is 70 mph, the stopping distance is 177 feet.
- We can set this up as a proportion: (70 mph)^2 / 177 feet = (55 mph)^2 / x.
Step 2: Solve for "x":
- To solve for "x," we need to cross-multiply and then divide:
(70 mph)^2 * x = 177 feet * (55 mph)^2.
x = (177 feet * (55 mph)^2) / (70 mph)^2.
x = (177 * 3025) / 4900.
x ≈ 108.045 feet.
Therefore, an Alfa Romeo going at 55 mph requires approximately 108.045 feet to stop.
To find the stopping distance required by an Alfa Romeo going at 115 mph, we can use the same proportion and follow a similar process:
Step 1: Set up a proportion using the given information:
- Let "y" represent the stopping distance required by an Alfa Romeo going at 115 mph.
- From the given information, we know that when the speed is 70 mph, the stopping distance is 177 feet.
- We can set this up as a proportion: (70 mph)^2 / 177 feet = (115 mph)^2 / y.
Step 2: Solve for "y":
- To solve for "y," we need to cross-multiply and then divide:
(70 mph)^2 * y = 177 feet * (115 mph)^2.
y = (177 feet * (115 mph)^2) / (70 mph)^2.
y = (177 * 13225) / 4900.
y ≈ 479.5 feet.
Therefore, an Alfa Romeo going at 115 mph requires approximately 479.5 feet to stop.
To find the stopping distance required by an Alfa Romeo going at 55 mph and at 115 mph, we can use the concept of proportional relationships and the given information.
According to the problem, the stopping distance is proportional to the square of the velocity. This means that if we know the stopping distance at one velocity, we can find the stopping distance at another velocity using the proportionality relationship.
Let's first calculate the stopping distance at 70 mph. According to Car and Driver, an Alfa Romeo going 70 mph requires 177 feet to stop. Let's call this stopping distance D1 and the velocity V1.
D1 = 177 feet
V1 = 70 mph
Now, let's calculate the stopping distance at 55 mph. Let's call this stopping distance D2 and the velocity V2.
D2 = D1 * (V2/V1)^2
= 177 * (55/70)^2
To calculate this, we need to find the ratio of velocities and square it. 55/70 ≈ 0.7857
So, (55/70)^2 ≈ 0.7857^2 ≈ 0.6173
D2 ≈ 177 * 0.6173
D2 ≈ 109.1681 feet
Therefore, an Alfa Romeo going at 55 mph requires approximately 109.1681 feet to stop.
Now, let's calculate the stopping distance at 115 mph. Let's call this stopping distance D3 and the velocity V3.
D3 = D1 * (V3/V1)^2
= 177 * (115/70)^2
To calculate this, we need to find the ratio of velocities and square it. 115/70 ≈ 1.6429
So, (115/70)^2 ≈ 1.6429^2 ≈ 2.6984
D3 ≈ 177 * 2.6984
D3 ≈ 477.9716 feet
Therefore, an Alfa Romeo going at 115 mph requires approximately 477.9716 feet to stop.
To summarize:
- A 55 mph Alfa Romeo requires approximately 109.1681 feet to stop.
- A 115 mph Alfa Romeo requires approximately 477.9716 feet to stop.
Keep in mind that these calculations are based on the assumption that the stopping distance is proportional to the square of the velocity.