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Math - Calculus

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Integration of (sinx + cosx)^2
from 0 to pi/2.
I get pi/2 + 1 as my final answer... wondering if that's correct?

  • Math - Calculus -

    Hmmm. Isn't (sin + cos)^2=1+2cosxsinx ?

    int(1+2cosx sinx)dx= x +sin^2 x

    over the limit= PI/2+1 -0-0= wow, your answer.

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