The gravitational potential difference between the surface of a planet and a point P, 10 m above the
surface, is 8.0 J kg-1. Assuming a uniform field, what is the value of the gravitational field strength
in the region between the planet’s surface and P?
effected region of a mass to attract another mass is called gravitational field
To find the value of the gravitational field strength between the planet's surface and point P, you can use the formula:
Gravitational field strength (g) = Gravitational potential difference (ΔV) / Height difference (h)
In this case, the gravitational potential difference (ΔV) is given as 8.0 J kg^-1, and the height difference (h) is 10 m.
Plugging these values into the formula, we have:
g = 8.0 J kg^-1 / 10 m
Now, let's calculate the value:
g = 0.8 J kg^-1 m^-1
Therefore, the value of the gravitational field strength in the region between the planet's surface and point P is 0.8 J kg^-1 m^-1.
To find the value of the gravitational field strength in the region between the planet's surface and point P, we can use the formula:
Gravitational field strength (g) = gravitational potential difference (ΔV) / height difference (Δh)
In this case, the gravitational potential difference is given as 8.0 J kg-1 and the height difference is 10 m.
Therefore, the gravitational field strength is:
g = 8.0 J kg-1 / 10 m
g = 0.8 N kg-1
So, the value of the gravitational field strength in the region between the planet's surface and point P is 0.8 N kg-1.
Note: The units of gravitational field strength are Newtons per kilogram (N kg-1) or meters per second squared (m/s²).
I assume you mean the gradient is uniform. And I assume you have calculus.
You have used terms Potential, and field strength, I hope you used them precisely . Field strength is the gradient of Potential.
Gravitational Field strength=d(potential diff/d height)
or "g"=8(J/kg)/10m=.8J/kg-m