The gravitational potential difference between the surface of a planet and a point P, 10 m above the

surface, is 8.0 J kg-1. Assuming a uniform field, what is the value of the gravitational field strength
in the region between the planet’s surface and P?

effected region of a mass to attract another mass is called gravitational field

To find the value of the gravitational field strength between the planet's surface and point P, you can use the formula:

Gravitational field strength (g) = Gravitational potential difference (ΔV) / Height difference (h)

In this case, the gravitational potential difference (ΔV) is given as 8.0 J kg^-1, and the height difference (h) is 10 m.

Plugging these values into the formula, we have:

g = 8.0 J kg^-1 / 10 m

Now, let's calculate the value:

g = 0.8 J kg^-1 m^-1

Therefore, the value of the gravitational field strength in the region between the planet's surface and point P is 0.8 J kg^-1 m^-1.

To find the value of the gravitational field strength in the region between the planet's surface and point P, we can use the formula:

Gravitational field strength (g) = gravitational potential difference (ΔV) / height difference (Δh)

In this case, the gravitational potential difference is given as 8.0 J kg-1 and the height difference is 10 m.

Therefore, the gravitational field strength is:

g = 8.0 J kg-1 / 10 m
g = 0.8 N kg-1

So, the value of the gravitational field strength in the region between the planet's surface and point P is 0.8 N kg-1.

Note: The units of gravitational field strength are Newtons per kilogram (N kg-1) or meters per second squared (m/s²).

I assume you mean the gradient is uniform. And I assume you have calculus.

You have used terms Potential, and field strength, I hope you used them precisely . Field strength is the gradient of Potential.

Gravitational Field strength=d(potential diff/d height)
or "g"=8(J/kg)/10m=.8J/kg-m