A resistor is connected across the terminals of a 6.00-V battery, which delivers 3.50 105 J of energy to the resistor in 11 hours. What is the resistance of the resistor?

^ This is wrong.

Energy =v2 x t/R

Energy=3.5 x 10^5
V=6
t=11 hours (turn into seconds)x 3600=39600 seconds
6^2 x 39600/3.5x10^5=4
R=4
Try for yourself:)

To find the resistance of the resistor, we can make use of Ohm's Law and the equation for power.

Ohm's Law states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R).

Mathematically, Ohm's Law is represented as:
I = V / R

And the equation for power is:
P = IV

Given:
Voltage (V) = 6.00 V
Energy (E) = 3.50 * 10^5 J
Time (t) = 11 hours

First, let's calculate the power (P) using the given energy and time:
P = E / t

Substituting the values:
P = 3.50 * 10^5 J / 11 hours

We need to convert the time from hours to seconds:
t = 11 * 3600 seconds
t = 39600 seconds

Now we can calculate the power:
P = 3.50 * 10^5 J / 39600 seconds

Next, let's calculate the current (I) by rearranging the power equation:
I = P / V

Substituting the values:
I = (3.50 * 10^5 J / 39600 seconds) / 6.00 V

Now we can calculate the current:
I = (3.50 * 10^5 J / 39600 seconds) / 6.00 V

Finally, we can calculate the resistance (R) by rearranging Ohm's Law:
R = V / I

Substituting the values:
R = 6.00 V / [(3.50 * 10^5 J / 39600 seconds) / 6.00 V]

Now we can calculate the resistance:
R = 6.00 V / [(3.50 * 10^5 J / 39600 seconds) / 6.00 V]

Simplifying the expression:
R = (6.00 V)^2 / (3.50 * 10^5 J / 39600 seconds)

Calculating the value:
R ≈ 2.22 Ω

Therefore, the resistance of the resistor is approximately 2.22 ohms.

ohms = ((seconds)(V^2))/J