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April 18, 2014

April 18, 2014

Posted by **Autumn** on Wednesday, January 19, 2011 at 12:49pm.

3/x^3/1/x^2

? Thanks

- Algebra II -
**helper**, Wednesday, January 19, 2011 at 1:09pm3/x^3 divided by 1/x^2

is this your problem?

instead of dividing, invert and multiply

3/x^3 * x^2/1 = 3x^2/x^3 = 3x^-1 = 3/x

- Algebra II -
**bryan**, Thursday, January 20, 2011 at 2:58pm-6/8 - 6/8 =

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