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January 24, 2015

January 24, 2015

Posted by **A-D** on Wednesday, January 19, 2011 at 5:56am.

use x=1st number

y=second number

z= 3rd number

please help...thanks a lot!!

- advance algebra -
**Reiny**, Wednesday, January 19, 2011 at 9:45amYou have 3 consecutive questions of this type.

Why do you want to use 3 variables, it is much easier to just define one, and the use the given to define the others.

e.g.

let the first number be x

then the 2nd number is 3x-6

and the 3rd is (2/3)(3x-6) + 2 = 2x -4 + 2 = 2x - 2

then x + 3x-6 + 2x-2 = 172

6x = 180

x = 30

1st = 30

2nd = 3(30)-6 = 84

3rd = 58

check: 30+84+58 = 172

try the others using only one variable.

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