Posted by G on Tuesday, January 18, 2011 at 10:53pm.
9x+6y=3 (1)
3x-7y=-26 (2)
using substitution method in (1) we get
9x+6y=3
dividing by 3 both side we get
3x+2y=1
taking 2y to the other side (here 2y in + so when we change its side it will be -)
3x=1-2y
(here 3 is multiply with x so when it goes other side sign will change in divide)
x=(1-2y)/3 (3)
3x-7y=-26 (2)
putting the value of x in (2) from (3)
3*(1-2y)/3-7y=-26
(3 will cancel by 3)
1-2y-7y=-26
1-9y=-26
taking constant no. Same side
-9y=-26-1
-9y=-27
(both sides minus sign will cancel by each other)
9y=27
y=27/9
y=3
putting the value of y in (3)
x=(1-3*2)/3
x=(1-6)/3
x=-5/3
(u can check ur ans by putting the value of 'x' and 'y' in (1) and (2))
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