A bar 5m long has a weight of 50nt attached to the other end is 80nt. Determine the magnitude, direction, and point of application of the equilibriant.
To determine the magnitude, direction, and point of application of the equilibrant, we need to understand the concept of equilibrium and apply the conditions for balanced forces.
In this scenario, we have a bar that is 5m long with a weight of 50N attached at one end, and another force of 80N applied at the other end.
First, let's consider the forces acting on the bar:
1. The weight of 50N acts downward at one end of the bar.
2. The applied force of 80N acts upward at the other end of the bar.
Since these two forces are in opposite directions, they create an unbalanced force, causing the bar to rotate in a clockwise direction. To bring the bar into equilibrium, we need to introduce an equal and opposite force, known as the equilibrant.
To determine the magnitude of the equilibrant, we need to find the resultant of the two given forces. The resultant is obtained by calculating the vector sum of the two forces:
Resultant = 80N - 50N (since they act in opposite directions)
Resultant = 30N
Therefore, the magnitude of the equilibrant is 30N.
The direction of the equilibrant is opposite to the resultant force. In this case, since the resultant force acts in the clockwise direction, the equilibrant will act in the counterclockwise direction.
The point of application of the equilibrant is at the same location as the resultant force, which is at the other end of the bar.
To summarize:
- Magnitude of the equilibrant: 30 Newtons (30N)
- Direction of the equilibrant: Counterclockwise
- Point of application of the equilibrant: At the other end of the bar
Remember, to determine the magnitude, direction, and point of application of the equilibrant, you need to analyze the forces acting on the object and apply the principles of equilibrium.