Posted by karla on .
What the solution of the equation: y^23y=9 ?

algebra 2 and trigonometry 
helper,
y^23y=9
y^2  3y = 9
complete the square
y^2  3y + 9/4 = 9 + 9/4
(y  3/2)^2 = 45/4
+ (y  3/2) = 45/4
solve for y
y = 3/2 (sqrt5 + 1)
y = 3/2 (1 + sqrt5)