The deepest place in the ocean is the Marianas Trench in the western Pacific

Ocean, which is over 11.0 km deep. On January 23, 1960, the research sub Trieste went to a depth of
10.915 km, nearly to the bottom of the trench. This still is the deepest dive on record. The density of
sea water is 1025 kg/m3.
(a) What is the water pressure at that depth? Express your answer in atmospheres (atm).
(b) What was the force due to water pressure on a flat section of area 1.0 m2 on the top of the sub’s
hull?

To find the water pressure at the depth of 10.915 km in the Marianas Trench, we can use the concept of hydrostatic pressure.

(a) The pressure at any point in a fluid at rest is given by the equation:

Pressure = Density x Gravity x Depth

Given:
Density of sea water = 1025 kg/m^3
Depth = 10.915 km = 10,915 m
Gravity = 9.8 m/s^2 (acceleration due to gravity)

So,
Pressure = 1025 kg/m^3 x 9.8 m/s^2 x 10,915 m

To express the pressure in atmospheres (atm), we need to convert it.

1 atmosphere (atm) is the average atmospheric pressure at sea level, which is approximately 101,325 Pascal (Pa).

To convert our pressure to atm, we divide by 101,325 Pa:

Pressure in atm = (1025 kg/m^3 x 9.8 m/s^2 x 10,915 m) / 101,325 Pa

Calculating this value will give us the water pressure at that depth in atmospheres.

(b) To find the force due to water pressure on a flat section of area 1.0 m^2 on the top of the sub's hull, we can use the formula:

Force = Pressure x Area

Given:
Pressure (from part a) = (Calculate the value)
Area = 1.0 m^2

Force = Pressure x Area
Force = (Calculate the value from part a) x 1.0 m^2

Calculating this value will give us the force due to water pressure on the top of the sub's hull.