I need to find out which structure is more correct:

Reaction of the compound C3H8O with CrO3 (oxidizing agent) yields acetone. Which of the three structures is more correct?

(My three structures are as follows: 1-propanol, 2-propanol, and methylethyl ether.)

I believe the answer is 2-propanol is oxidized to acetone.

To determine which structure is more correct, we need to compare the structures of the given compounds and their reactions with CrO3.

1. Propanol (C3H8O): It is an alcohol with a hydroxyl group (OH) attached to the middle carbon atom. When propanol reacts with CrO3, it undergoes oxidation, resulting in the formation of propanal (CH3CH2CHO), not acetone.

2. 2-Propanol (C3H8O): It is also an alcohol, but with the hydroxyl group attached to the secondary carbon atom. When 2-propanol reacts with CrO3, it undergoes oxidation, resulting in the formation of acetone (CH3COCH3), which is consistent with the given reaction.

3. Methylethyl ether (C3H8O): It is an ether compound with two carbon atoms bonded to an oxygen atom. Ethers do not typically undergo oxidation reactions with CrO3, so it is unlikely to yield acetone in this reaction.

Based on the given reaction and the known reactions of these compounds with CrO3, the structure of 2-propanol seems to be more correct because it yields acetone upon reaction with CrO3.