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Posted by **Maggie** on Tuesday, January 18, 2011 at 5:55pm.

What is the surface area of a right circular cylinder with base circle of radius of 5m and height of the cylinder 10m?

- Math -
**helper**, Tuesday, January 18, 2011 at 6:16pmr = 5, h = 10

SA = 2 pi r^2 + 2 pi r h

SA = 2(3.14)(5^2) + 2(3.14)(5)(10)

SA = 2(3.14)(25) + 2(3.14)(5)(10)

SA = 50(3.14) + 100(3.14)

SA = 157 + 314 = 471 m^2

- Math -
**Maggie**, Tuesday, January 18, 2011 at 6:28pmThanks math helper but I am more lost than before since my choices for an answer are 25pi m2, 166.67pi m2,33.3pi m2, 100pi m2

I don't know what I am missing here. I am sorry to bother you.

- Math -
**helper**, Tuesday, January 18, 2011 at 7:29pmr = 5, h = 10

SA = 2 pi r^2 + 2 pi r h

SA = 2(pi)(5^2) + 2(pi)(5)(10)

SA = 2(pi)(25) + 2(pi)(5)(10)

SA = 50pi + 100pi

SA = 150 pi m^2

do you have the formula for a right circular cylinder?

I've checked my math and I get 150pi m^2

if you can post the formula from your book I can check

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