Posted by kriti on Tuesday, January 18, 2011 at 4:30pm.
y'=4t^3-36t= 4t(t^2-9)=4t(t+3)(t-3)
y"=12t^2-36=12(t^2-3)=12(t+sqrt3)(t-sqrt3)
so when t=less than sqrt3, y"=+ *- or negagive, slowing down.
t= greater than sqrt3, y"=+ * + speeding up.
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