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April 18, 2014

April 18, 2014

Posted by **kriti** on Tuesday, January 18, 2011 at 4:30pm.

- calculus -
**bobpursley**, Tuesday, January 18, 2011 at 4:36pmy'=4t^3-36t= 4t(t^2-9)=4t(t+3)(t-3)

y"=12t^2-36=12(t^2-3)=12(t+sqrt3)(t-sqrt3)

so when t=less than sqrt3, y"=+ *- or negagive, slowing down.

t= greater than sqrt3, y"=+ * + speeding up.

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