A body falls from rest for 5seconds calculate its velocity-time graph of its motion (from t= 0s to t=5s)
To calculate the velocity-time graph of an object falling from rest, we first need to understand the relationship between velocity and time for a falling object.
When an object falls freely under the influence of gravity, its velocity increases uniformly with time. This means that the velocity-time graph will be a straight line, sloping upward.
The equation that describes this relationship is:
v = g * t,
where v represents the velocity, g is the acceleration due to gravity (which is approximately 9.8 m/s^2 on Earth), and t is the time.
To calculate the velocity at different time points, we can substitute the values of time into the equation.
Let's calculate the velocity at specific time points from t = 0s to t = 5s.
- At t = 0s, the object starts from rest, so the initial velocity is 0 m/s.
- At t = 1s, the velocity can be calculated using the equation:
v = g * t = 9.8 m/s^2 * 1s = 9.8 m/s.
- Similarly, we can calculate the velocity at other time points:
t = 2s: v = 9.8 m/s^2 * 2s = 19.6 m/s.
t = 3s: v = 9.8 m/s^2 * 3s = 29.4 m/s.
t = 4s: v = 9.8 m/s^2 * 4s = 39.2 m/s.
t = 5s: v = 9.8 m/s^2 * 5s = 49 m/s.
Now we have the velocities at different time points, and we can plot them on a graph.
On the y-axis, we plot the velocity (m/s), and on the x-axis, we plot the time (s). Then, we connect the points with a straight line.
The graph will start at (0,0) and go through the points (1,9.8), (2,19.6), (3,29.4), (4,39.2), and (5,49).
This represents the velocity-time graph of the object falling from rest over the given time interval.