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posted by Felipe on Monday, January 17, 2011 at 7:23pm.

how many grams of oxygen are in 213.5g Fe2O3?

213.5g Fe2O3 x (1 mole Fe2O3/molar mass Fe2O3) x (3 atoms oxygen/1 mole Fe2O3) x (16 g oxygen/1 mole O atoms) =

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