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April 18, 2015

Homework Help: Chemistry

Posted by Anonymous on Monday, January 17, 2011 at 6:54pm.

"The analyzer said that at 20degreesC the unknown gas was 82.8% carbon by weight and 17.2% hydrogen. The analyzer also diffused the gas through a special apparatus and measured the rate of its diffusion compared to how fast oxygen gas diffused under the same conditions. The rates of diffusion were 5.0cm(cubed)/sec for oxygen gas and 3.7cm(cubed)/for unknown gas. With this information figure out the molecular formula for the unknown gas

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