Math
posted by Hannah .
Solve integration using u substitution of (x+1)sqrt(2x)dx

integrate (x+1)sqrt(2x)dx
u = (sqrt(2  x))
u^2 = 2  x
x = 2  u^2
 2u du = dx
I = integral sign
I (2  u^2 + 1)u 2u du
I (3  u^2)2u^2 du
I (6u^2 + 2u^4) du
6 I u^2 du + 2 I u^4 du
2 I u^4 du  6 I u^2 du
2 (1/5 u^5)  6 (1/3 u^3)
2/5 u^5  2u^3
substitute back in for u = (sqrt(2x))
2/5(sqrt(2x))^5  2(sqrt(2x))^3