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July 29, 2014

July 29, 2014

Posted by **Hannah** on Monday, January 17, 2011 at 6:08pm.

- Math -
**helper**, Monday, January 17, 2011 at 6:36pmintegrate (x+1)sqrt(2-x)dx

u = (sqrt(2 - x))

u^2 = 2 - x

x = 2 - u^2

- 2u du = dx

I = integral sign

I (2 - u^2 + 1)u -2u du

I (3 - u^2)-2u^2 du

I (-6u^2 + 2u^4) du

-6 I u^2 du + 2 I u^4 du

2 I u^4 du - 6 I u^2 du

2 (1/5 u^5) - 6 (1/3 u^3)

2/5 u^5 - 2u^3

substitute back in for u = (sqrt(2-x))

2/5(sqrt(2-x))^5 - 2(sqrt(2-x))^3

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