Posted by Brittney on Monday, January 17, 2011 at 4:16pm.
Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 9 less than twice the number of pennies; the number of dimes she has is 19 less than three times the number of pennies. How many coins of each kind does she have?

algebra  helper, Monday, January 17, 2011 at 4:37pm
p = pennies
2p  9 = nickles
3p  19 = dimes
p + 2p  9 + 3p  19 = 140
6p  28 = 140
6p = 168
p = 28
p = pennies = 28
2p  9 = nickles = 47
3p  19 = 65

algebra  Lisa, Monday, February 7, 2011 at 3:17pm
there are 100 coins. ten are dimes. the rest are pennies and nickles. there are twice as many pennies as nickles. how many pennies and nickles are in the jar?

algebra  Chanelle, Tuesday, January 29, 2013 at 11:04am
Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 12 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?
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