Posted by **Brittney** on Monday, January 17, 2011 at 4:16pm.

Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 9 less than twice the number of pennies; the number of dimes she has is 19 less than three times the number of pennies. How many coins of each kind does she have?

- algebra -
**helper**, Monday, January 17, 2011 at 4:37pm
p = pennies

2p - 9 = nickles

3p - 19 = dimes

p + 2p - 9 + 3p - 19 = 140

6p - 28 = 140

6p = 168

p = 28

p = pennies = 28

2p - 9 = nickles = 47

3p - 19 = 65

- algebra -
**Lisa**, Monday, February 7, 2011 at 3:17pm
there are 100 coins. ten are dimes. the rest are pennies and nickles. there are twice as many pennies as nickles. how many pennies and nickles are in the jar?

- algebra -
**Chanelle**, Tuesday, January 29, 2013 at 11:04am
Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 12 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?

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