mat h
posted by kevin on .
ms. buxx invested a total of $2000 in two savings accounts. The first account pays 3% interest per year and the second account pays 5% interest per yera. If the interest from both accounts totals $84 per yera, how much is invested in each account?

x = amt at 3%
y = amt at 5%
x + y = 2000
.03x + .05y = 84
solve simultaneously for x, y
give it a try, post if you need for help
x = 800, y = 1200 if you are right 
the answer is the first account has 800 and the second account has 1200

I need the steps to this equation

x+y=2000
.03x+.05y=84
x+y=2000
x x
y=x+2000 y=(800)+2000
.03x+.05(x+2000)=84 y=1200
.03x+ .05x +100=84
.02x+100=84
100 100
.02x=16

.02x
x= 800