Posted by kevin on Monday, January 17, 2011 at 10:50am.
Let V = motorist speed
a = officer acceleration
a) V*t = (1/2)a t^2
Solve for t when they are at same place
b) a*t = cop speed at time t
c) (1/2) at^2 = cop displacement at time t
= (1/2)(2V/a)^2*a = 2 V^2/a
Related Questions
physics - A motorist drives along a straight road at a constant speed of 15.0 m/...
physics - A motorist drives along a straight road at a constant speed of 15.0 m/...
Physics - A motorist drives along a straight road at a constant speed of 16.5 m/...
Physics - A motorist traveling with a constant speed of 15m/s passes a school-...
Physics - A motorist traveling with a constant speed of 15m/s passes a school-...
Physics - A motorist drives along a straight road at a constant speed of 60 m/s...
physics - A speeding motorist traveling 125 km/h passes a stationary police ...
physics - A speeding motorist traveling 105 km/h passes a stationary police ...
Physics - A motorist traveling at 30 m/s passes a parked police car. At the ...
physics - A police officer in hot pursuit drives her car through a circular ...
For Further Reading