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July 31, 2014

July 31, 2014

Posted by **Anon** on Monday, January 17, 2011 at 7:40am.

- Combinatorics -
**Reiny**, Monday, January 17, 2011 at 10:10amso the groups could be 3,5 ; 4,4 ; or 5,3

for a total of C(8,3)xC(5,5) + C(8,4)xC(4,4) + C(8,5)xC(3,3)

= 56 + 70 + 56 = 182

I am assuming that the two groups can be distinguished.

If not, then it would simply be 56+70

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