Posted by deena on Monday, January 17, 2011 at 3:39am.
WE know that [formula a^m/a^n=a^(m-n)]
where m>n it means in division when base (means 'a') are same with different power('m' and 'n') then powers are subtracted
x^3*y/[(y^1/2)*(x^-2)]
=x^3-(-2)*y^(1-1/2)
=x^3+2*y^1/2
=x^5*y^1/2
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