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September 30, 2014

September 30, 2014

Posted by **jerf** on Sunday, January 16, 2011 at 8:44pm.

- physics -
**bobpursley**, Sunday, January 16, 2011 at 9:27pmDraw the diagram.

label the base of the ladder A, the top P, the corner O, and the cg C.

OA=3, AP=5, and you can compute OP as 4

OA^2+OP^2=AB^2

2 OA doa/dt +2 OP dop/dt=0 by taking the derivative (AB is a constant)

well, you know OA, OP, doa/dt=2, you can find dop/dt. At that instant, the center C has a velocity (1/2 doa/dt horizontal, and 1/2 dop/dt vertical)

so you have to add those two components as a vector

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