Posted by **motlhalefi** on Sunday, January 16, 2011 at 7:56am.

x-3y=1

x2-2xy+9y2=17 solve simalteneously

- math -
**Reiny**, Sunday, January 16, 2011 at 8:48am
from the 1st ----> x = 3y+1

(3y+1)^2 - 2y(3y+1) + 9y^2 = 17

9y^2 + 6y + 1 - 6y^2 - 2y + 9y^2 = 17

12y^2 + 4y -16 = 0

3y^2 + y - 4 = 0

(3y + 4)(y - 1) = 0

y = -4/3 or y = 1

if x = -4/3, y = 3(-4/3) + 1 = -3

if x = 1 , y = 3(1) + 1 = 4

btw, it is "simultaneously"

- correction - math -
**Reiny**, Sunday, January 16, 2011 at 9:29am
You probably figured it out yourself by at the end it should have said ...

if y = -4/3, x = 3(-4/3) + 1 = -3

if y = 1 , x = 3(1) + 1 = 4

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