Posted by bharat narke on Sunday, January 16, 2011 at 2:47am.
That will depend upon the angle A that the bar makes with the vertial axis.
The torque due to the weight of the bar, measuered about the pivot, but equal the applied torwue, F*L
F*L = M*g*sin A*(L/2)
(L/2 is the distance of the center of m,ass from the pivot).
Solve for F. L cancels out
F = (M g sinA)/2
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