Posted by Ivan on Sunday, January 16, 2011 at 12:44am.
A lot is in the shape of a trapezoid. The sum of the bases is 180 feet. If the area of the lot is 8,100 square feet, what is the distance across the lot, i.e., the altitude of the figure?
The altitude of the trapezoid is how many feet?

Geometry  Henry, Sunday, January 16, 2011 at 7:09pm
A = ((B1 + B2)/2)h = 8100F^2.
(180 / 2)h = 8100,
90h = 8100,
h = 8100 / 90 = 90Ft = Distance across
the lot.