Posted by lYDIA on Sunday, January 16, 2011 at 12:06am.
The nth term of an arithmetic progression is defined by N = a + (n-1)d where N = the nth term, a = the first term and d = the common difference.
Therefore,
85 = 100 + (6 - 1)d
-15 = 5d making d = -3
The 50th term then becomes
N(50) = 85 + (50 - 1)(-3) = ?
-402
ah what!!!!!!!!!!!!!!!!!!!
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