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March 28, 2015

March 28, 2015

Posted by **Justine** on Saturday, January 15, 2011 at 11:54pm.

- Algebra -
**Marth**, Sunday, January 16, 2011 at 12:22amx^2-6x-3=0

x = (-b +/- sqrt(b^2-4ac))/(2a)

x = (6 +/- sqrt(6^2 - 4(1)(-3)) ) / (2(1))

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