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December 20, 2014

December 20, 2014

Posted by **aldren** on Saturday, January 15, 2011 at 11:16pm.

x+y+z=39

16x=13z

- math -
**Reiny**, Sunday, January 16, 2011 at 8:25amfrom the 1st : y = 10/13

from the 3rd: x = 13z/16

sub into 2nd

x+y+z = 39

(13z/16) + 10/13 + z = 9

times 208

169z + 160 + 208z = 1872

377z = 1712

z = 1712/377

now back-substitute ....

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