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posted by aldren on Saturday, January 15, 2011 at 11:16pm.
13y=10 x+y+z=39 16x=13z
from the 1st : y = 10/13 from the 3rd: x = 13z/16 sub into 2nd x+y+z = 39 (13z/16) + 10/13 + z = 9 times 208 169z + 160 + 208z = 1872 377z = 1712 z = 1712/377 now back-substitute ....
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