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September 4, 2015

Homework Help: math

Posted by rose on Saturday, January 15, 2011 at 10:56pm.

solve this in 3 variables..
i don't know where to start,,:((

y/4+z/3-x/2=4
y/2-x/6+z/15=2
y/8+z/5-x/3=2

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