A 5.00-gram sample of glucose, C6H12O6, [molar mass = 180.] is dissolved 10.0 grams of water

What is the molality of the glucose solution?

Calculate the boiling(BP) and freezing points(FP) of this solution to the nearest 0.1 C°.

The vapor pressure of pure water at 30ºC is 25.0 torr. What is the vapor pressure of the solution described above at 30°C?

moles glucose = grams/molar mass

Solve for moles.

m = #moles/L soln
You know #moles from above and you know L soln. Solve for m.

f.p.
delta T = Kf*m, then solve for f.p. knowing normal f.p. is 0C.

b.p.
delta T = Kb*m, then solve for b.p. knowing normal b.p. is 100 C.

mole fraction water = moles H2O/total # moles (that is, moles water + moles glucose), then
Psoln = XH2O*25.0 torr.

To find the molality of the glucose solution, you need to first calculate the moles of glucose and the mass of water in the solution.

1. Start by finding the moles of glucose:
- Given that the molar mass of glucose is 180 g/mol and the sample has a mass of 5.00 grams, you can calculate the moles of glucose using the formula:
moles = mass / molar mass
moles = 5.00 g / 180 g/mol

2. Next, calculate the mass of water in the solution, which is given as 10.0 grams.

3. Now, you can calculate the molality of the glucose solution using the formula:
molality = moles of solute / mass of solvent in kg
- Convert the mass of water to kg by dividing by 1000:
mass of water in kg = 10.0 g / 1000

- Plug in the values into the formula:
molality = moles of glucose / mass of water in kg

To calculate the boiling point and freezing point of the solution, you need to use the colligative properties of the solution:

1. Boiling Point Elevation:
- The boiling point elevation is calculated using the formula:
ΔTB = Kbm
where ΔTB is the change in boiling point, Kb is the molal boiling point constant of water (0.512 °C/m), and m is the molality of the solution.

- Plug in the values into the formula to find the boiling point elevation.

2. Freezing Point Depression:
- The freezing point depression is calculated using the formula:
ΔTF = Kfm
where ΔTF is the change in freezing point, Kf is the molal freezing point constant of water (1.86 °C/m), and m is the molality of the solution.

- Plug in the values into the formula to find the freezing point depression.

To find the vapor pressure of the solution at 30°C, you can use Raoult's law:

1. Raoult's Law:
- According to Raoult's law, the vapor pressure of a solution is given by the formula:
p = Xs * Ps
where p is the vapor pressure of the solution, Xs is the mole fraction of the solute, and Ps is the vapor pressure of the pure solvent.

- Calculate the mole fraction of the solute by dividing the moles of glucose by the total moles of solute and solvent (moles of glucose + moles of water).

- Finally, plug in the values into the formula to find the vapor pressure of the solution at 30°C.