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December 19, 2014

December 19, 2014

Posted by **Anonymous** on Saturday, January 15, 2011 at 10:08pm.

- college math 209 -
**helper**, Saturday, January 15, 2011 at 10:14pmis this the equation ?,

2(sqrt5) + 3/(sqrt5) - 1

2(sqrt5) + 3(sqrt5)/5 - 1

to get rid of the radical in 3/(sqrt5).

multiply 3/(sqrt5)*sqrt5/sqrt5 = 3(sqrt5)/5

- college math 209 -
**bryan**, Thursday, January 20, 2011 at 2:40pm-6/8 - 6/8 =

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