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chemistry

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the concentration of a chemical degrades in water according to order kinetics. the degradation constant is 0.2 day^-1. if the initial concentration is 100.0 mg/L, how may days are required for the concentration to reach 0.14 mg/L?

  • chemistry - ,

    You didn't post the order.

  • chemistry - ,

    The concentration of a chemical degrades in water according to order kinetics. the degradation constant is 0.2 day^-1. if the initial concentration is 100.0 mg/L, how many days are required for the concentration to reach 0.14 mg/L?

  • chemistry - ,

    You still didn't post the order. If we assume first order (a guess on my part) then
    k = 0.693/t1/2
    k = 0.693/0.2 = ??

    ln(No/N) = kt
    No = 100.0 mg/L
    N =0.14 mg/L
    k = from above.
    t = unknown
    Solve for t in days.

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