Posted by **Jenna** on Saturday, January 15, 2011 at 4:17pm.

Using the procedure of comlpeting the square, write the equation x^2+y^2-6x+8y=0 in the form (x-h)^2+(y-k)^2=r^2.

state the domain and range

where(h,k) is the center of the circle and r is the radius

- math 20 -
**bobpursley**, Saturday, January 15, 2011 at 9:25pm
first,

(x^2-6x + ?)+(y^2+8y+?)=?

we need (-3)^3 in the x, and 4^2 in the y

(x^2-6x+9)+(y^2+8y+16)=9+16

(x-3)^2 + (y+4)^2=5^2

- math 20 -
**kyle**, Sunday, January 16, 2011 at 12:36am
how did u get -3^3 and 4^2?

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