Posted by **Tory Smith** on Saturday, January 15, 2011 at 3:55pm.

A university bookstore recently sold a wirebound graph-paper notebook for $2.64, and a college-ruled notebook for $3.61. At the start of spring semester, a combination of 50 of these notebooks were sold for a total of $168.86. How many of each type were sold?

- Math -
**helper**, Saturday, January 15, 2011 at 5:50pm
x = number of graph notebooks

y = number of college ruled notebooks

2.64x = total value sold graph notebooks

3.61y = total value sold college notebooks

x + y = 50

2.64x + 3.61y = 168.86

Solve these 2 equations together by elimination or substitution method

I will use substitution method

x + y = 50

x = 50 - y

2.64x + 3.61y = 168.86

2.64(50 - y) + 3.61y = 168.86

132 - 2.64y + 3.61y = 168.86

132 + .97y = 168.86

.97y = 36.86

y = 38

substitute y = 38 in x + y = 50, to find x

x + 38 = 50

x = 12

12 graph notebooks were sold

38 college ruled notebooks were sold

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