the perimeter of isosceles triangle is 70 d. of the length of a leg of the triangle is 5 dm less than twice the lenth of the base, find the lengths of the sides of the triangle.
math - PsyDAG, Saturday, January 15, 2011 at 10:14am
Let x = length of base, then 2x-5 = length of legs (sides).
2(2x-5) + x = 70
Solve for x.