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Posted by on Saturday, January 15, 2011 at 8:40am.

the perimeter of isosceles triangle is 70 d. of the length of a leg of the triangle is 5 dm less than twice the lenth of the base, find the lengths of the sides of the triangle.

  • math - , Saturday, January 15, 2011 at 10:14am

    Let x = length of base, then 2x-5 = length of legs (sides).

    2(2x-5) + x = 70

    Solve for x.

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