Posted by Rachael on Saturday, January 15, 2011 at 7:13am.
There is nothing wrong with your answer and your math appears ok but the reasoning is out of this world. You apparently picked 9 as a starting point (and it's good that you did); however, if you had picked any other number it wouldn't have given you the correct answer. Here is a (there are several) conventional way of doing it.
0.9% solution = 0.9g/100 g solution (which is the same as substituting into the percent equation as
%NaCl = (g NaCl/100 mL)*100 = (0.90 g NaCl/100 mL)*100 =0.9% NaCl. Now if we want 2.00 L, just multiply by the factor of what you want over what you have; i.e., (0.90g NaCl) x (2,000 mL/100 mL) = 18 g
Related Questions
chemistry - Isotonic saline is often given to patients intravenously to ...
chemistry - Isotonic saline and is often given to patients intravenously to ...
chemistry - Isotonic saline is a 0.9%(g/100ml) solution of salty water. You are ...
math - a pharmacist mixed some 10% saline solution with some 15% saline solution...
chem 4 - How many grams of sodium chloride are needed to make 1 L of 0.9% (m/v...
chemistry - the normal concentration of sodium chloride in blood is 0.9%(w/v). ...
chemistry - A saline solution was prepared by dissolving 5.45 g sodium chloride ...
Algebra - A saline solution was made by mixing 11 ml of a 36% saline solution ...
Chemistry - The normal concentration of sodium chloride in blood is 0.9% (w/v). ...
math - you have an unlimited supply of 5% saline solution and 8% saline solution...
For Further Reading