If you had excess aluminum, how many moles of aluminum chloride could be produced from 32.0 g of chlorine gas?

Here is a solved example of a stoichiometry problem similar to the one you posted. Just follow the steps. Post your work if you get stuck.

http://www.jiskha.com/science/chemistry/stoichiometry.html

To determine the number of moles of aluminum chloride that could be produced from 32.0 g of chlorine gas, we need to first calculate the number of moles of chlorine gas. Then, we can use the balanced chemical equation to determine the molar ratio between chlorine gas and aluminum chloride.

The molar mass of chlorine gas (Cl₂) is 2 * 35.45 g/mol = 70.90 g/mol.

To calculate the number of moles of chlorine gas:
moles of chlorine gas = mass / molar mass
moles of chlorine gas = 32.0 g / 70.90 g/mol

Now, let's calculate the number of moles of chlorine gas:
moles of chlorine gas = 0.451 mol

According to the balanced chemical equation for the reaction between aluminum and chlorine gas:

2 Al + 3 Cl₂ → 2 AlCl₃

The molar ratio between chlorine gas and aluminum chloride is 3:2. This means that for every 3 moles of chlorine gas, we will produce 2 moles of aluminum chloride.

Now, let's calculate the number of moles of aluminum chloride that could be produced:
moles of aluminum chloride = (moles of chlorine gas / 3) * 2
moles of aluminum chloride = (0.451 mol / 3) * 2

Now, let's calculate the number of moles of aluminum chloride:
moles of aluminum chloride = 0.301 mol

Therefore, from 32.0 g of chlorine gas, you could produce approximately 0.301 moles of aluminum chloride.

To determine the number of moles of aluminum chloride that can be produced from 32.0 g of chlorine gas, we need to first determine the balanced chemical equation for the reaction between aluminum and chlorine to form aluminum chloride.

The balanced chemical equation for the reaction is:

2 Al + 3 Cl2 → 2 AlCl3

From the equation, we can see that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride.

Now, we need to calculate the number of moles of chlorine gas present in 32.0 g. To do this, we use the molar mass of chlorine gas, which is 70.90 g/mol.

Number of moles of chlorine gas = mass of chlorine gas / molar mass of chlorine gas

Number of moles of chlorine gas = 32.0 g / 70.90 g/mol

Number of moles of chlorine gas ≈ 0.4519 mol

Since the reaction stoichiometry shows that 2 moles of aluminum chloride are produced for every 3 moles of chlorine gas, the number of moles of aluminum chloride can be calculated using the mole ratio.

Number of moles of aluminum chloride = (Number of moles of chlorine gas / 3) × 2

Number of moles of aluminum chloride = (0.4519 mol / 3) × 2

Number of moles of aluminum chloride ≈ 0.3013 mol

Therefore, approximately 0.3013 moles of aluminum chloride can be produced from 32.0 g of chlorine gas.