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A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m?

  • Chemistry - ,

    moles = grams/molar mass
    Solve for moles.

    molality = moles/kg solvent
    Solve for molality

    delta T = Kf*molality
    Solve for delta T, then for the freezing point knowing the normal freezing point is zero C.

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