Posted by **Robert** on Friday, January 14, 2011 at 12:21am.

Michelle sold tickets for the basketball game. Each adult ticket costs 3$ and each student ticket costs 1.50. There were 105 tickets sold for a total of 250$. How many of each type of ticket were sold?

- Algebra -
**helper**, Friday, January 14, 2011 at 12:25am
x = adult tkts

y = student tkts

3x = value of adult tkts

1.5y = value of student tkts

x + y = 105

3x + 1.5y = 250

solve these equation together

for your answer

post back if you need more help

- Algebra -
**Robert**, Friday, January 14, 2011 at 12:30am
How do you solve the equations? ):

- Algebra -
**helper**, Friday, January 14, 2011 at 1:01am
(1) x + y = 105

(2) 3x + 1.5y = 250

multiply equation (1) by -3

-3 (x + y = 105) = -3x - 3y = -315

add the two equations together

-3x - 3y = -315

3x + 1.5y = 250

0 - 1.5y = - 65

-1.5y = -65

y = 43.33 student tkts

x + y = 105

x + 43.33 = 105

x = 61.67 student tkts

are you sure you typed this problem right?

because there were 61.67 adult tkts

and 43.33 student tkts

the number of tkts should not be a fraction, but I checked this 4 times

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