Posted by Taylor on Friday, January 14, 2011 at 12:05am.
Some how TRAIN A travelling at 36 m/s, is accidentally sidetracked onto the train track for TRAIN A. The TRAIN A engineer spots TRAIN A 100 m ahead on the same track and travelling in the same direction. The engineer jams on the brakes and slows TRAIN B at a rate of 3m/s^2. TRAIN A's conductor was unaware of the situation. If the speed of the local train is 11 m/s will the express be able to stop in time or will there be a collision?
Support you answer with a calculation.
Please help me solve this ASAP, thank you.

Physics  Taylor, Friday, January 14, 2011 at 12:07am
Sorry Train A is sidetracked onto Train B's train track, which is 100 m ahead of Train A**

Physics  hh, Wednesday, September 14, 2011 at 11:42am
v=0
u=36m/s
a=3m/s^2
t=?
v=u+at
0=36m/s3m/s^2t
0=36=3t
t=36/2
=18 seconds.
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