Posted by **Taylor** on Friday, January 14, 2011 at 12:05am.

Some how TRAIN A travelling at 36 m/s, is accidentally sidetracked onto the train track for TRAIN A. The TRAIN A engineer spots TRAIN A 100 m ahead on the same track and travelling in the same direction. The engineer jams on the brakes and slows TRAIN B at a rate of 3m/s^2. TRAIN A's conductor was unaware of the situation. If the speed of the local train is 11 m/s will the express be able to stop in time or will there be a collision?

Support you answer with a calculation.

Please help me solve this ASAP, thank you.

- Physics -
**Taylor**, Friday, January 14, 2011 at 12:07am
Sorry Train A is sidetracked onto Train B's train track, which is 100 m ahead of Train A**

- Physics -
**hh**, Wednesday, September 14, 2011 at 11:42am
v=0

u=36m/s

a=3m/s^2

t=?

v=u+at

0=36m/s-3m/s^2t

0=-36=3t

t=36/2

=18 seconds.

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